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If a spring extends by x on loading, the...

If a spring extends by `x` on loading, then the energy stored by the spring is (if T is tension in the spring and k is spring constant)

A

`(T^(2))/(2x)`

B

`(T^(2))/(2K)`

C

`(2x)/(T^(2))`

D

`(2T^(2))/(2k)`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) `U=(1)/(2)Fl=(F^(2)l)/(2AY)" "` [F and Y are constant]
`U prop (1)/(r^(2))`
`therefore (U_(A))/(U_(B))=((l_(A))/(l_(B)))xx((r_(B))/(r_(A)))=(3)xx((1)/(2))^(2)=(3)/(4)`
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