The temperature of an iron piece is heated from `30^@ C "to" 90^@ C`. What is the change in its temperature on the fahrenheit scale and on the kelvin scale?

Explanation

Given, `DeltaC=90^(@)-30^(@)=60^(@)C`
Temperture difference on Fahrenheit scale,
`DeltaF(9)/(5)DeltaC=(9)/(5)(60^(@)C)=108^(@)F`
Temperature difference on kelvin scale, `DeltaK=DeltaC=60K`