The volume of mercury in the bulb of thermometer is `10^(-6) m^(3)`. The area of cross-section of the capillary tube is `2 xx 10^(-7) m^(2)`. If the temperature is raised by `100^(0)C`, the increase in the length (in cm) of the mercury column is `(gamma_(Hg) = 18 xx 10^(-5//@)C)`

Answer

9

Explanation

By cubical expansion relaction, `DeltaV =V xx gamma Delta T`
where `gamma =18 xx10^(-5)//"^(@)C,`
and initial volume, `V = 10^(-6) m^(3)`
Temperature, `Delta T = 100^(@)C`
Putting these vlues in Eq. (i), we get
`DeltaV =10^(-6)xx18xx10^(-5)xx10^(2)=18xx10^(-9) m^(3)`
`"Since" " " DeltaV=AxxDeltal`
`therefore" " 18xx10^(-2)=2xx10^(-7)xxDeltal`
or `" " 9xx10^(-2)= Deltal or Deltal=9cm`