A clock which keeps correct time at `20^(@)C` is subjected to `40^(@)C.` If coefficient of linear expansion of the pendulum is `12xx10^(-6)//"^(@)C.` How much will it gain or loss in time ?

Explanation

To solve the problem of how much the clock will gain or lose in time when subjected to a temperature change, we can follow these steps:

### Step 1: Identify the given values
- Coefficient of linear expansion (α) = \( 12 \times 10^{-6} \, \text{°C}^{-1} \)
- Initial temperature (T1) = \( 20 \, \text{°C} \)
- Final temperature (T2) = \( 40 \, \text{°C} \)
- Change in temperature (Δθ) = T2 - T1 = \( 40 - 20 = 20 \, \text{°C} \)
- Total time in a day (T) = \( 24 \, \text{hours} = 24 \times 3600 \, \text{seconds} = 86400 \, \text{seconds} \)
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