For a molecule of an ideal gas `n=3xx10^(8)cm^(-3)` and mean free path is `10^(-2)` cm. Calculate the diameter of the lomecule.

Explanation

To calculate the diameter of a molecule of an ideal gas given the number density \( n \) and the mean free path \( \lambda \), we can use the formula:

\[ \lambda = \frac{1}{\sqrt{2} \pi n d^2} \]

Where:
- \( \lambda \) is the mean free path,
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