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4 g hydrogen is mixed with 11.2 litre of...

`4 g` hydrogen is mixed with 11.2 litre of He at (STP) in a container of volume 20 litre. If the final temperature is `300 K`, find the pressure.

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`because` `4g` hydrogen `=2` moles hydrogen.
`therefore` `11.2L` He at STP `=1/2` mole of He
According to Dalton's law of partial pressure
`p=p_(H)+p_(He)=(n_(H)+n_(He))(RT)/V=(2+1/2)(8.31xx(300K))/((20xx10^(-3))m^(3))`
`=3.12xx10^(5)N//m^(2)`
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