Find the average kinetic energy per molecule at temperature T for an equimolar mixture of two ideal gases A and B, where A is monoatmic and B is diamtomic.

Explanation

Number of degree of freeedom per molecule for A=3 Number of degrees of freedom per molecule for B=5 Since, the mixture is equimoolar, the average kinetic energy per molecule will be the simple average of the two calues i.e., `((3+5)/2)` kT = 4kT. Where k is Boltzmann's constant.