One mole of an ideal monoatomic gas is t...

One mole of an ideal monoatomic gas is taken at a temperature of `300 K`. Its volume is doubled keeping its pressure constant. Find the change in internal energy.

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Since, pressure is constant
`therefore" " VpropTtherefore(V_(i))/T_(i)=(V_(f))/T_(f)`
`therefore" " T_(f)=(V _(f))/V_(i)TirArrT_(f)=2T_(i)=600K`
`therefore" " DeltaU=f/2n.RDeltaT=3/2R(600-300)=450R`

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