Aperfect gas at `27^(@) C` is heated at constant pressure soas to duuble its volume. The increase in temperature of the gas will be

Options

A. `600 ^(@)C`
B. `327 ^(@)C`
C. `54^(@)C`
D. `300^(@)C`

Answer

D

Explanation

We know for derfect gas,V `prop` T
Here `" "(V_(1))/(V_(2))=(T_(1))/(T_(2))`
According to the question,
`V_(1)=V,"then"V_(2)=2Vand T_(1)=300K`
`therefore" "1/2=(300)/(T_(2))rArrT_(2)=600KrArrT_(2)=327^(@)C`
So, `" "Deltat = 327- 27 = 300^(@)C`