Two different isotherms representing the relationship between pressure p and volume V at a given temperature of the same ideal gas are shown for masses `m_(1)` and `m_(2)` then

Options

A. `m_(1) gt m_(2)`
B. `m_(1) = m_(2)`
C. `m_(1) lt m_(2)`
D. Nothing can be predicted

Answer

C

Explanation

`pV = muRT = m/MRT`

For 1 st graph, `" "p=(m_(1))/(M)(RT)/(V_(1))`
For 2nd graph, `" "p=(m_(2))/(M)(RT)/(V_(1))`
Fore eqs. (i) and (ii), we get
`" " (m_(1))/(m_(2))=(V_(1))/(V_(2))rArrmpropV`
As `" "V_(2)gt V_(1) rArrm_(1)gtm_(2)`