At `27^(@)C` temperature, the kinetic energy of an ideal gas is `E_(1^.)` If the temperature is increassed to `327^(@)C,` then the kinetic energy will be

Options

A. `(E_(1))/sqrt2`
B. `sqrt2 E`
C. `2E_(1)`
D. `(E_(1))/2`

Answer

C

Explanation

`E=3/2kTrArr E prop T`
`therefore" "(E_(2))/(E_(1))=(T_(2))/(T_(1))=(600)/(300)=2rArr E_(2)=2E_(1)`