The gas in a vessel is subjected to a pressure of `20` atmosphere at a temperature `27^(@)C`. The pressure of the gas in the vessel after one half of the gas is released from the vessel and the temperature of the remainder is raised by `50^(@)C` is

Options

A. 8.5 atm
B. 10.8 atm
C. 11.7 atm
D. 17 atm

Answer

C

Explanation

As, `pV= muRT =m/MRT rArr20xxV=m/MxxRxx300" "...(i)`
When m= m/2 and p=p' then
`" "p'=xxV=((m//2)/M)Rxx350" "...(ii)`
From Eqs. (i) and (ii), we get
`" "p'(140)/(12)~~11.7` atm