A metal rod of silver at `0^(@)C` is heated to `100^(@)C` . It's length is increased by `0.19 cm` . Coefficient of cubical expansion of the silver rod is

Options

A. `5.7xx10^(-5)//C`
B. `0.63xx10^(-5)//C`
C. `1.9xx10^(-5)//C`
D. `16.1xx10^(-5)//C`

Answer

A

Explanation

`alpha=(DeltaL)/(L_(o)(Deltatheta))=(0.19)/(100(100-0))=1.9xx10^(-5)//^(@)C`
Now, `gamma=3alpha=3xx1.9xx10^(-5)//^(@)C=5.7xx10^(-5)//^(@)C`