Find the average kinetic energy per molecule at temperature T for an equimolar mixture of two ideal gases A and B, where A is monoatmic and B is diamtomic.

Options

A. 2 kT
B. 4 kT
C. 3 kT
D. 8 kT

Answer

B

Explanation

Number of degrees of freedom per molecule for A = 3. Number of degress of freedom per molecule for B= 5. Since, the maxture is equimolar, the average kinetic energy pre molecule will be the simple average of the two values i.e., `((3+5)/2)` kT = 4kT where, k is Boltzmann's constant.