A current I flows in a conducting wire of lenth L. If we bent it in a circular form, then calculate its magnetic dipole moment.

Explanation

Let a wire of length L is bent in a circular form of raidus r.
Then `2pir=L=Rightarrow=(L)/(2pi) ……………..(i)`

The magnetic dipole moment of a circular ring,
`" " M=IA " " ("where, A is area of the ring")`
`or" " M=Ipir^(2) `
`" " M=Ipi((I)/(2pi))^(2)`
`" " M=Ipixx(L^(2))/(4pi^(2)`
`" " M=(IL^(2))/(4pi)A-m^(2)`