A magnetic needle is free to oscillate in a uniform magnetic field as shown in the figure. The magnetic moment of magnetic needle `7.2Am^(2)` and moment of inertia `I=6.5xx10^(-6)kgm^(2)`. The number of oscillation performed in 5s os 10. Calculate the magnitude of magnetic field?
Text Solution
AI Generated Solution
To solve the problem step by step, we will follow these calculations:
### Step 1: Calculate the Time Period (T)
Given that the number of oscillations performed in 5 seconds is 10, we can find the time period (T) of one oscillation.
\[
T = \frac{\text{Total time}}{\text{Number of oscillations}} = \frac{5 \text{ s}}{10} = 0.5 \text{ s}
\]
...
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