The horizontal and veritical components of eaths's field at a place ar 0.22 gauss of 0.38 gauss, respectively. Calculate the angle of dip and resultant intensity of earth's field.
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Here, H=0.002G, V=0.38G `Now, " " tan theta=(V)/(H)=(0.38)/(0.22)=1.7272` `therefore "Angle of dip", delta=59^(@)56'` Resulting mangetic field of the earth is `" " B=sqrt(H^(2)+V^(2))=sqrt(0.002^(2)+0.38^(2))=0.427G`
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