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The hysteresis loss for a specimen of ir...

The hysteresis loss for a specimen of iron weighing 15kg is equivalent at `300Jm^(-3)cycle^(-1)` Find the loss of energy per hour at 25 cycle `s^(-1)`. Density of iron is `7500kg m^(-3)`

Text Solution

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Let Q be th energy dissipated per unit volume per hystersis cycle in the given sample. Then the total energy lost by the volume V of the sample in time t will be
`" "W=QxxVxxvxxt`
where v is the number of hysteresis cycle per second.
Here `Q=300Jm^(-1)"cycle"^(-1),v=25"cycle"s^(-1),t=1h=3600s`
Volume, `V=("Mass")/("Density")=(15)/(7500)m^(3)`
`therefore "Hysteresis loss", W=300xx(15)/(7500)xx25xx3600J=5400J`
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