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A particle of charge q and mass m moves ...

A particle of charge `q` and mass `m` moves in a circular orbit of radius `r` with angular speed `omega`. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

A

`-(q)/(2m)`

B

`(qomegar^(2))/(2)`

C

`(qomega)/(2mr^(2))`

D

`(qomegar^(2))/(2m)`

Text Solution

Verified by Experts

The correct Answer is:
A
The relation between magnetic moment `(mu_(1))` and angular momentum (l) is
`mu_(1)=-(q)/(2m)l Rightarrow (mu_(1))/(l)=-(q)/(2m)`
The negative sighn indicates that the angular momentum of the electron is opposite in directin to the magnetic moment.
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