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The couple acting on a magnet of length ...

The couple acting on a magnet of length 10cm and pole strength 15A-m, kept in a field of `B=2xx10^(-5)`, at an anlge of `30^(@)` is

A

`1.5xx10^(-5)N-m`

B

`1.5xx10^(-3)N-m`

C

`1.5xx10^(-2)N-m`

D

`1.5xx10^(-6)N-m`

Text Solution

Verified by Experts

As, `tau=MB sin theta=(mxx2l)xx2xx10^(-5)sin30^(@)`
`=15xx10xx10^(-2)xx(1)/(2)=1.5xx10^(-5)N-m`
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