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The time period of a freely suspended ba...

The time period of a freely suspended bar magnet in a field is 2s. It is cut into two equal parts along its axis, then the time period is

A

4s

B

0.5s

C

2s

D

0.25s

Text Solution

Verified by Experts

As, time period T=`2pisqrt((I)/(MB)`
`T=2s, I'=(I)/(2),M'Rightarrow T' RightarrowT RightarrowT'=2s`
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