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A short bar magnet pleaced with its axis...

A short bar magnet pleaced with its axis at `30^(@)` with a uniform external magnetic field of `0.16` Tesla expriences a torque of magnitude `0.032` Joule. The magnetic moment of the bar magnet will be

Text Solution

Verified by Experts

The correct Answer is:
B
Magnetic moment of the bar magnet is given by
`tau=MB sin theta`
`therefore M=(tau)/(Bsintheta)`
`=(0.032)/(0.16xxsin theta)=(0.32xx2)/(0.16)=0.4jT^(-1)`
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