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A bar magnet when placed at an angle of ...

A bar magnet when placed at an angle of `30^(@)` to the direction of magnetic field field induction of `5xx10^(-2)T`, experiences a moment of couple `25xx10^(-6) N-m`. If the length of the magnet is 5cm its pole strength is

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The correct Answer is:
A

As, `tau=MB sin theta`
`tau=m(2L)Bsin theta`
`=(0.032)/(0.16xx10sin30^(@))=(0.032xx2)/((0.05)(5xx10^(-2)sin30^(@))=2xx10^(-2))A-m`
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