Home
Class 12
PHYSICS
A magnet of magnetic moment M is situate...

A magnet of magnetic moment `M` is situated with its axis along the direction of a magnetic field of strength `B`. The work done in rotating it by an angle of `180^(@)` will be

A

` - MB`

B

`+ MB`

C

zero

D

` + 2 MB`

Text Solution

Verified by Experts

The correct Answer is:
D

Work done in rotating the magnet from angle `theta_(1) "to angle" theta_(2)` is given by,
`W=MB(costheta_(1)-costheta_(2))`
`Here, theta_(1)=0^(@) and theta_(2)=180^(@)`
`W=MB(cos 0^(@)-cos 180^(@))=2MB`
Promotional Banner

Similar Questions

Explore conceptually related problems

A magnet of magnetic moment 20 A - m^(2) is freely suspended is a uniform magnetic field of strength 6 T . Work done to rotate it by 60^(@) will be .

A magnet of magnetic moment M is rotated through 360^(@) in a magnetic field H, the work done will be

A "bar" magnet of magnetic moment 1.5J//T is aligned with the direction of a uniform magnetic field of 0.22 T . The work done in turning the magnet so as to align its magnetic moment opposite to the field and the torque acting on it in this position are respectively.

If a magnetic dipole of moment M situated in the direction of a magnetic field B is rotated by 180^(@) , then the amount of work done is

As loop of magnetic moment M is placed in the orientation of unstable equilbirum position in a uniform magnetic field B . The external work done in rotating it through an angle theta is

A magnet of magnetic moment 2JT^(-1) is aligned in the direction of magnetic field of 0.1T . What is the net work done to bring the magnet normal to the magnrtic field?

A bar magnet of magnetic moment M is aligned parallel to the direction of a uniform magnetic field B. Calculate work done to align the magnetic moment (i) opposite to the field (ii) normal to field direction?