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When 2 amperes current is passed through...

When `2` amperes current is passed through a tangent galvanometer, it gives a deflection of `30^(@)`. For `60^(@)` deflection, the current must be

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The correct Answer is:
D
For a tangent galvanometer, if I amp current flows through coil, then this current is proprtional to angle of deflection (of the neddle)
`I alpha tan theta`
`(I_(1))/(I_(2))=(tan theta_(1))/(tan theta_(2)) Rightarrow (N_(1))/(N_(2))=(tan60^(@))/(tan45^(@))=sqrt3`
`I_(2)=6A`
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