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Two short magnets of equal dipole moment...

Two short magnets of equal dipole moments `M` are fastened perpendicularly at their centres (figure). The magnitude of the magnetic field at a distance `d` from the centre on the bisector of the right angle is
(##HCV_VOL2_C36_E01_006_Q01##)

A

`(mu_(0))/(4pi)(M)/(d^(3))`

B

`(mu_(0))/(4pi)(sqrt(2)M)/(d^(3))`

C

`(mu_(0))/(4pi)(2sqrt(2)M)/(d^(3))`

D

`(mu_(0))/(4pi)(2M)/(d^(3))`

Text Solution

Verified by Experts

The correct Answer is:
B
`B=(mu_(0))/(4pi) (M)/(d^(3))`

`therefore B_("net")=(mu_(0))/(4pi) (sqrt2M)/(d^(3)`
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