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A magnet makes 40 oscillations per minut...

A magnet makes `40` oscillations per minute at a place having magnetic field intensity of `0.1xx10^(-5)T`. At another place, it takes 2.5 sec to complete one vibrating. The value of earth's horizontal field at that place is

A

`0.25xx10^(-6)T`

B

`0.36xx10^(6)T`

C

`0.66xx10^(-8)T`

D

`1.2xx10^(-6)T`

Text Solution

Verified by Experts

The correct Answer is:
B
Time period, T= `2pisqrt(1/(MB))`
`therefore " " T alpha (1)/(sqrtB)`
`therefore " " (T_(1))/(T_(2))=sqrt(B_(2)/(B_(1)`
`Rightarrow (60//40)/(2.5)=sqrt(B_(2)/(0.1xx10^(-5)))`
`therefore B_(2)=0.36xx10^(-6)T`
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