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A dip circle is adjusted so that its nee...

A dip circle is adjusted so that its needle moves freely in the magnetic meridian. In this position, the angle of dip is `40^(@)`. Now the dip circle is rotated so that the plane in which the needle moves makes an angle of `30^(@)` with the magnetic meridian. In this position the needle will dip by an angle

A

`40^(@)`

B

`30^(@)`

C

more than `40^(@)`

D

less than `40^(@)`

Text Solution

Verified by Experts

The correct Answer is:
C
Apparent dip, `theta'=tan^(-1)((V')/(H'))`
`tan^(-1)=((V)/(H cos 30^(@)))=tan^(-1)((2)/(sqrt3).theta)`
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