A paramagnetic sample shows a net magnetization of `8Am^-1` when placed in an external magnetic field of `0*6T` at a temperature of `4K`. When the same sample is placed in an external magnetic field of `0*2T` at a temperature of `16K`, the magnetization will be

Options

A. `(32)/(3)Am^(-1)`
B. `(2)/(3)Am^(-1)`
C. `6Am^(-1)`
D. `2.4Am^(-1)`

Answer

B

Explanation

As Curve law example law explains, we can deduce a formula for the relation between magnetic field induction, temperature and megnetisation,
`i.e. I("magnetisaton")alpha (B"magentic field induction")/(t("temperature in kelvin"))`
`(I_(2))/(I_(1))=(B_(2))/(B_(1))xx(t_(1))/(t_(2))`
`I_(1)=8Am^(-1)`
` " " B_(1)=0.63T, T_(1)=4K`
` " " B_(2)=0.2T, T_(2)=16K,I_(2)=?`
`(0.2)/(0.6)xx(4)/(16)=I_(2)/(8) Rightarrow I_(2)=8xx(1)/(12)=(2)/(3)Am^(-1)`