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A tangent galvanometer has a coil of 50 ...

A tangent galvanometer has a coil of 50 turns and a radius of 20cm. The horizontal component of the earth's magnetic field is `B_H = 3 xx 10^(-5) T`. Find the current which gives a deflection of `45^@)`.

A

0.39A

B

0.29A

C

0.19A

D

0.09A

Text Solution

Verified by Experts

The correct Answer is:
C
`Given, B_(H)=3xx10^(-2)T, theta=45^(@),n=50`
`and " " r=20xx10^(-2)m`
`"As, the current, I=(2rB_(H))/(mu_(0)n)tan theta`
`" " (2xx20xx10^(-2)xx3xx10xxtan45^(@))/(4pixx10^(-7)xx50)`
`" " =(120xx10^(-7))/(4pixx10^(-7)xx50)=(3)/(5pi)=(3)/(5xx3.14)=(3)/(15.7)=0.19A`
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