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The intensity of magnetization of a bar ...

The intensity of magnetization of a bar magnet is `5xx10^(4)A-m^(-1)`. The magnetic length and the area of cross section of the magnet are 12cm and `1cm^(-2)` respectively. The magnitude of magnetic moment of this bar magnet (in SI unit) is.

A

0.6

B

1.3

C

1.2

D

2.4

Text Solution

Verified by Experts

The correct Answer is:
A

We know that intensity of magnetisation, `I=(M)/(V)`
where, M= magnetic moment V=volume
So, `So, M=IV=5xx10^(4)xx(12)/(100)xx(1)/((100))^(2)`
`" "=60xx10^(4)xx10^(-6)=0.6A-m^(2)`
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