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An alectron in a circular orbit of radi...

An alectron in a circular orbit of radius 0.05 mn performs `10^(16) "rev"//s.` the magnetic moment due to this ratation of electron is `(in A-m^(2)).`

A

`2.16xx10^(-23)`

B

`3.21xx10^(-22)`

C

`3.21xx10^(-24)`

D

`1.26xx10^(-23)`

Text Solution

Verified by Experts

The correct Answer is:
D
Given, `r=0.05nm=0.05xx10^(-9)m " " "["therefore1nm=10^(-9)"]"`
`" "n=10^(16)"revolution"`
`and " " e=16xx10^(-19)C`
We know that the magnitic that the magnetic moment, M=AI
`M=pir^(2)xx"ne"=3.14xx(0.05xx10^(-9))^(2)xx10^(16)xx1.6xx10^(-19)`
`or " " =10xx^(-23)A-m^(2)`
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