A bar magnet of lenth l and magnetic dip...

A bar magnet of lenth `l` and magnetic dipole moment 'M' is bent in the form of an arc as shown in figure. The new magnetic dipole moment will be

A

M

B

`(3)/(pi)M`

C

`(2)/(pi)M`

D

`(M)/(2)`

Verified by Experts

The correct Answer is:

B

Let the magnetic pole strength be m then =ml
`" "M'=m(2r(sin60)/(2))^(@)where (r(pi)/(3))=l`
`" "M'=2m((3l)/(pi))((1)/(2)) (3ml)/(pi)=(3M)/(pi)`

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