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A steel wire of length l has a magnetic ...

A steel wire of length l has a magnetic moment M. It is bent into a semicircular arc. What is the new magnetic moment?

A

`Mxxl`

B

`(M)/(l)`

C

`(2M)/(pi)`

D

M

Text Solution

Verified by Experts

The correct Answer is:
C
When wire is bent in the form of semicircular are the, `I=pir`
`therefore`The radius of semicircular are, `r=l/pi`
Distance between two end points of semicircular wire
Magnetic moment of semicircular wire
But ml is the magnetic straight wire i.e. ml=M
`therefore "New Magnetic moment" =(2)/(pi)M`
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