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A conducing circular loop is placed in a...

A conducing circular loop is placed in a uniform magnetic field of indution `B` tesla with its plane normal to the field. Now, radius of the loop starts shrinking at the rate `(dr//dt)`. Then the induced e.m.f. at the instant when the radius is `r` is:

A

`pirB(dr//dt)`

B

`2pirB(dr//dt)`

C

`pir^(2)(dB//dt)`

D

`(pir^(2)//2)B(dr//dt)`

Text Solution

Verified by Experts

The correct Answer is:
B

Induced emf, `e=B.(dS)/(dt)=2pirB.(dr)/(dt)`
where, `(dr)/(dt)` is the rate at which radius of loop is shrinking.
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