A long solenoid has 500 turns. When a cu...

A long solenoid has `500` turns. When a current of `2A` is passed through it, the resulting magnetic flux linked with each turn of the solenoid is `4xx10^(-3)Wb` . The self-inductance of the solenoid is

1.0 H

4.0 H

2.5 H

2.0 H

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The correct Answer is:

We have, `Nphi_(B)=Li`
Self-inductance, `L=(Nphi_(B))/(i)=(500xx4xx10^(-3))/(2)=1H`

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