The current passing through a choke coil of `5` hery is decreasing at the rate of `2 ampere//sec`. The e.mf. Devlopeing across the coil is

Options

A. 10 V
B. `-10 V`
C. 2.5 V
D. `-2.5 mV`

Answer

A

Explanation

Given, `(di)/(dt)=2A//s and L=5H`
`therefore` The emf developing across the coil,
`e=L(di)/(dt)=5xx2=10V`