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Two coils of self-inductance L(1) and L(...

Two coils of self-inductance `L_(1)` and `L_(2)` are placed closed to each other so that total flux in one coil is completely linked with other. If `M` is mutual inductance between them, then

A

`M=L_(1)L_(2)`

B

`M=L_(1)//L_(2)`

C

`M=sqrt(L_(1)L_(2))`

D

`M=(L_(1)L_(2))^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C

Mutual inductance between two coils,
`M=-(e_(2))/((di_(1)//dt))=-(e)/((di_(2)//dt))`
Also, `e_(1)=-L_(1)(di_(1))/(dt)and e_(2)=-L_(2)(di_(2))/(dt)`
`therefore" "M^(2)=(e_(1)e_(2))/(((di_(1))/(dt))((di_(2))/(dt)))=L_(1)L_(2)rArrM=sqrt(L_(1)L_(2))`
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