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A coil has an area of 0.05 m^(2) and it ...

A coil has an area of `0.05 m^(2)` and it has `800` turns. It is placed perpendicular in a magnitude field of strength `4xx10^(-5)Wb//m^(2)`, it is rotated through `90^(@)` in `0.1` sec. the average e.m.f. induced in the coil is

A

0.056 V

B

0.046 V

C

0.026 V

D

0.016 V

Text Solution

Verified by Experts

The correct Answer is:
D
Induced emf,
`e=|(-NBA(costheta_(2)-costheta_(1)))/(Deltat)|`
`=|-(800xx4xx10^(-5)xx0.05(cos90^(@)-cos0^(@)))/(0.1)|=0.016V`
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