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A rectangular loop with a sliding connec...

A rectangular loop with a sliding connector of length `10 cm` is situated in uniform magnetic field perpendicular to plane of loop. The magnetic induction is `0.1` tesla and resistance of connector `(R )` is `1 ohm`. The sides `AB` and `CD` have resistances `2 ohm` and `3 ohm` respectively. Find the current in the connector during its motion with constant velocity one

A

`(1)/(242)A`

B

`(1)/(220)A`

C

`(1)/(55)A`

D

`(1)/(440)A`

Text Solution

Verified by Experts

The correct Answer is:
B
`e=Bvl=(0.1)(1)(0.1)=(1)/(100)V`
Net resistance `=1+(2xx3)/(2+3)=(11)/(5)Omega`
`therefore` Current, `i=((1//100)/(11//5))=(1)/(220)A`
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