A wire of length 10cm translates in a direction making an angle of `60^@` with its length. The plane of motion is perpendicular ot a uniform magnetic field of 1.0 T that exists in the space. Find the emf induced between the ends of the rod if the speed of translation of `20 cm s^(-1)`.

Options

A. `1.7xx10^(-3)V`
B. `17xx10^(-3)V`
C. `0.17xx10^(-3)V`
D. `1.7xx10^(-4)V`

Answer

B

Explanation

Due to v `cos 60^(@), e= 0`
Due to v `sin 60^(@), e=B(v sin 60^(@))l`
`=(sqrt3)/(2)Bvl=(sqrt3)/(2)xx1xx0.2xx0.1=17xx10^(-3)V`