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The loop ABCD is moving with velocity 'v...

The loop `ABCD` is moving with velocity `'v'` towards right. The magnetic field is `4T`. The loop is connected to a resistance of `8 Omega`. If steady current of `2A` flows in the loop then value of `'v'` if loop has a resistance of `4 Omega`, is : (Given `AB = 30 cm, AD = 30 cm`)

A

`(50)/(3)ms^(-1)`

B

`20ms^(-1)`

C

`10ms^(-1)`

D

`(100)/(3)ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`"Current, I"=("Potential difference")/("Resistance")`
`therefore` Potential difference `=2xx12=24V=Bvl`
Here, l = AD `sin 37^(@)=0.3xx(3)/(5)=0.18m`
`therefore"Velocity, v"=(24)/(Bl)=(24)/(4xx0.18)=(100)/(3)ms^(-1)`
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