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The phase difference between the flux li...

The phase difference between the flux linkage and the induced e.m.f. in a rotating coil in a uniform magnetic field

A

`pi//2`

B

`pi//3`

C

`-pi//6`

D

`pi`

Text Solution

Verified by Experts

The correct Answer is:
A

The flux is given bu
`phi=B.A`
`phi=|B"||"A|cos theta`
Also, induced emf, `epsilon=-(dphi)/(dt)=(d[|B||A|cos theta])/(dt)`
`=-|B||A|(d(costheta))/(dt)=|B||A|sintheta.omega`
`rArr" "epsilon=BAomegacos (theta-pi//2)`
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