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A conductor of length 5 cm is moved para...

A conductor of length 5 cm is moved paralllel to itself with a speed of `2m//s`, perpendicular to a uniform magnetic field of `10^(-3) Wb//m^(2).` the induced emf generated is

A

`2xx10^(-3)V`

B

`1xx10^(-3)V`

C

`1xx10^(-4)V`

D

`2xx10^(-4)V`

Text Solution

Verified by Experts

The correct Answer is:
C
As, e= Bvl
Here, B=`10^(-3)Wb//m^(3)`
v =2m/s
l = 5 cm = 0.05 m
`therefore" emf, e"=(10^(-3))(2)(0.05)=1xx10^(-4)V`
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