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A rectangular coil of 100 turns and size...

A rectangular coil of 100 turns and size `0.1mxx0.05m` is placed perpendicular to a magnetic field of 0.1 T. If the field drops to 0.05 T in 0.05 s, the magnitude of the emf induced in the coil is

A

`sqrt2`

B

`sqrt3`

C

`sqrt(0.6)`

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
D
Given, n= 100 turns, A = `0.1xx0.05m^(2)`
`B_(1)=0.1T, B_(2)=0.05T, dt=0.05s`
We know that,
`e=|(-dphi)/(dt)|=|(d)/(dt)("n B A cos"theta)|=|(nAdBcos theta)/(dt)|`
Here, `theta=0`
`therefore" "e=|(nAdB)/(dt)|=|(100xx0.1xx0.05xx(0.1-0.05))/(0.05)|`
`rArr" e = 0.5 V`
None of the option is correct.
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Knowledge Check

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