If emf induced in a coil is 2V by changing the current in it from 8 A to 6 A in `2 xx 10^(3)` s . Then , the coefficient of self -induction is

Options

A. `2xx10^(-3)H`
B. `10^(-3)H`
C. `0.5xx10^(-3)H`
D. `4xx10^(-3)H`

Answer

A

Explanation

Induced emf, e = 2 V
`i_(1)=8A, i_(2)=6A`
`Deltat=2xx10^(-3)s`
Coefficient of self-induction,
`L=(e)/(Deltai//Deltat)=(-2)/((6-8)//2xx10^(-3)`
`=(-2xx2xx10^(-3))/(-2)`
`=2xx10^(-3)H`