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A 60muF capacitor is connected to a 110V...

A `60muF` capacitor is connected to a 110V, 60 Hz AC supply determine the rms value of the curent in the circuit.

Text Solution

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As `I_(rms) = (V_(rms)/X_(c))`
where, `X_(c) = 1/(omegaC) = 1/(2pifC)`
Here, C=`60muF=60 xx 10^(-6)F,V_(rms)`=110V, f=60Hz
So, `X_(C) = 1/(2 xxpi xx 60 xx 60 xx 10^(-6))Omega`
`therefore I_(rms) = 110 xx 2 xx 3.14 xx 3600 xx 10^(-6)`
=2.49 A
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