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An alternating emf 200 virtual volts at ...

An alternating emf 200 virtual volts at `50 Hz` is connected to a circuit resistance `1omega` and inductance `0.01 H`. What is the phase difference between the current and the emf in the circuit? Also, find the virtual current in the circuit.

Text Solution

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In case of an AC, the voltage leads the current in phase by an angles.
`phi = tan^(-1)(X_(L)/R)`
Here, `X_(L) = omegaL=(2pifL)= (2pi)(50)(0.01)=piOmega`
and `R=1Omega`
`therefore phi=tan^(-1)(pi)=72.3^(@)`
Further, `I_(rms) = (V_(rms))/|Z|= V_(rms)/(sqrt(R^(2) + X_(L)^(2)))`
Substituting the values we have,
`I_(rms) = 200/((sqrt((1)^(2)+(pi)^(2))))`=60.67A
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