Home
Class 12
PHYSICS
In an AC circuit, a resistance of Rohm i...

In an AC circuit, a resistance of `Rohm` is connected is series with an inductance `L`. If phase angle between volage and current be `45^(@)`, the value of inductive reactance will be

A

R / 4

B

R / 2

C

R

D

cannot be found with the given data

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

In an A.C. circuit, a resistance R=40 Omega and an inductance L are connected in series. If the phase angle between voltage and current is 45^(@) , then the value of the inductive reactance will be

An inductor (L) and resistance (R) are connected in series with an AC source. The phase difference between voltage (V) and current (i) is 45^(@) . Now a capacitor (C) is connected in series with L-R, If the phase difference between V and i remain same, then capacitive reactance and impedance of L-C-R circuit will be-

An inductance and a resistance are connected in series with an AC potential . In this circuit

In a simple circuit with resistance, phase between AC emf and AC current is

The phase angle between current and voltage in a purely inductive circuit is

A series LCR circuit, has equal resistance capacitive reactance. What is the phase angle between voltage across generator and resistor ?

In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be

In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be