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An AC voltage is applied to a resistance...

An `AC` voltage is applied to a resistance `R` and an inductance `L` in series. If `R` and the inductive reactance are both equal to `3 Omega`, the phase difference between the applied voltage and the current in the circuit is

A

` pi `/ 4

B

` pi ` / 2

C

zero

D

` pi `/ 6

Text Solution

Verified by Experts

The correct Answer is:
A
`tan phi`= `underset(L)(X)`/R = `Lomega`/R
tan`phi` = `3Omega`/`3Omega` `implies` tan`phi` = 1
`phi` = `tan^(-1)(1)` `implies` `phi` = `45^(@)`
`phi` = `pi`/4 rad
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